TSTP Solution File: PUZ140^2 by Duper---1.0
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% File : Duper---1.0
% Problem : PUZ140^2 : TPTP v8.1.2. Released v6.4.0.
% Transfm : none
% Format : tptp:raw
% Command : duper %s
% Computer : n004.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 300s
% DateTime : Thu Aug 31 13:14:52 EDT 2023
% Result : Theorem 3.53s 3.76s
% Output : Proof 3.53s
% Verified :
% SZS Type : -
% Comments :
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.12/0.12 % Problem : PUZ140^2 : TPTP v8.1.2. Released v6.4.0.
% 0.12/0.13 % Command : duper %s
% 0.13/0.34 % Computer : n004.cluster.edu
% 0.13/0.34 % Model : x86_64 x86_64
% 0.13/0.34 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.34 % Memory : 8042.1875MB
% 0.13/0.34 % OS : Linux 3.10.0-693.el7.x86_64
% 0.13/0.34 % CPULimit : 300
% 0.13/0.34 % WCLimit : 300
% 0.13/0.34 % DateTime : Sat Aug 26 22:13:38 EDT 2023
% 0.13/0.34 % CPUTime :
% 3.53/3.76 SZS status Theorem for theBenchmark.p
% 3.53/3.76 SZS output start Proof for theBenchmark.p
% 3.53/3.76 Clause #1 (by assumption #[]): Eq (∀ (S : syrup), And (Eq (coffee_mixture S) coffee) (hot (coffee_mixture S))) True
% 3.53/3.76 Clause #2 (by assumption #[]): Eq (Not (Exists fun SyrupMixer => ∀ (S : syrup), Exists fun B => And (And (Eq B (SyrupMixer S)) (Eq B coffee)) (hot B)))
% 3.53/3.76 True
% 3.53/3.76 Clause #5 (by clausification #[1]): ∀ (a : syrup), Eq (And (Eq (coffee_mixture a) coffee) (hot (coffee_mixture a))) True
% 3.53/3.76 Clause #6 (by clausification #[5]): ∀ (a : syrup), Eq (hot (coffee_mixture a)) True
% 3.53/3.76 Clause #7 (by clausification #[5]): ∀ (a : syrup), Eq (Eq (coffee_mixture a) coffee) True
% 3.53/3.76 Clause #8 (by clausification #[7]): ∀ (a : syrup), Eq (coffee_mixture a) coffee
% 3.53/3.76 Clause #10 (by backward demodulation #[8, 6]): Eq (hot coffee) True
% 3.53/3.76 Clause #11 (by clausification #[2]): Eq (Exists fun SyrupMixer => ∀ (S : syrup), Exists fun B => And (And (Eq B (SyrupMixer S)) (Eq B coffee)) (hot B)) False
% 3.53/3.76 Clause #12 (by clausification #[11]): ∀ (a : syrup → beverage), Eq (∀ (S : syrup), Exists fun B => And (And (Eq B (a S)) (Eq B coffee)) (hot B)) False
% 3.53/3.76 Clause #13 (by clausification #[12]): ∀ (a : syrup → beverage) (a_1 : syrup),
% 3.53/3.76 Eq (Not (Exists fun B => And (And (Eq B (a (skS.0 0 a a_1))) (Eq B coffee)) (hot B))) True
% 3.53/3.76 Clause #14 (by clausification #[13]): ∀ (a : syrup → beverage) (a_1 : syrup),
% 3.53/3.76 Eq (Exists fun B => And (And (Eq B (a (skS.0 0 a a_1))) (Eq B coffee)) (hot B)) False
% 3.53/3.76 Clause #15 (by clausification #[14]): ∀ (a : beverage) (a_1 : syrup → beverage) (a_2 : syrup),
% 3.53/3.76 Eq (And (And (Eq a (a_1 (skS.0 0 a_1 a_2))) (Eq a coffee)) (hot a)) False
% 3.53/3.76 Clause #16 (by clausification #[15]): ∀ (a : beverage) (a_1 : syrup → beverage) (a_2 : syrup),
% 3.53/3.76 Or (Eq (And (Eq a (a_1 (skS.0 0 a_1 a_2))) (Eq a coffee)) False) (Eq (hot a) False)
% 3.53/3.76 Clause #17 (by clausification #[16]): ∀ (a : beverage) (a_1 : syrup → beverage) (a_2 : syrup),
% 3.53/3.76 Or (Eq (hot a) False) (Or (Eq (Eq a (a_1 (skS.0 0 a_1 a_2))) False) (Eq (Eq a coffee) False))
% 3.53/3.76 Clause #18 (by clausification #[17]): ∀ (a : beverage) (a_1 : syrup → beverage) (a_2 : syrup),
% 3.53/3.76 Or (Eq (hot a) False) (Or (Eq (Eq a coffee) False) (Ne a (a_1 (skS.0 0 a_1 a_2))))
% 3.53/3.76 Clause #19 (by clausification #[18]): ∀ (a : beverage) (a_1 : syrup → beverage) (a_2 : syrup),
% 3.53/3.76 Or (Eq (hot a) False) (Or (Ne a (a_1 (skS.0 0 a_1 a_2))) (Ne a coffee))
% 3.53/3.76 Clause #20 (by destructive equality resolution #[19]): ∀ (a : syrup → beverage) (a_1 : syrup), Or (Eq (hot coffee) False) (Ne coffee (a (skS.0 0 a a_1)))
% 3.53/3.76 Clause #21 (by superposition #[20, 10]): ∀ (a : syrup → beverage) (a_1 : syrup), Or (Ne coffee (a (skS.0 0 a a_1))) (Eq False True)
% 3.53/3.76 Clause #22 (by clausification #[21]): ∀ (a : syrup → beverage) (a_1 : syrup), Ne coffee (a (skS.0 0 a a_1))
% 3.53/3.76 Clause #23 (by equality resolution #[22]): False
% 3.53/3.76 SZS output end Proof for theBenchmark.p
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